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JEE Main 2024 Chemistry question

ChemistryEquilibriumJEE Main 2024

For a certain thermochemical reaction M → N at T = 400 K, ΔH° = 77.2 kJ mol⁻¹, ΔS = 122 JK⁻¹, log equilibrium constant (log K) is – × 10⁻¹.

Answer: 37

Solution

ΔG° = ΔH° − TΔS° = 77200 − 400 × 122 = 28400 J. Also ΔG° = −2.303RT log K,

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Question ID VK-016620