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JEE Main 2024 Chemistry question

ChemistryElectrochemistryJEE Main 2024

The hydrogen electrode is dipped in a solution of pH = 3 at 25°C. The potential of the electrode will be – × 10⁻² V. (2.303RT/F = 0.059 V)

Answer: 18

Solution

For 2H⁺ + 2e⁻ → H₂: E = 0 + (0.059/2) log[H⁺]² = 0.059 log[H⁺] = −0.059 × pH

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Question ID VK-016621