JEE Main 2024 Mathematics question

The coefficient of x²⁰¹² in the expansion of (1 – x)²⁰⁰⁸(1 + x + x²)²⁰⁰⁷ is equal to .

Answer: 0

Solution

(1 − x)²⁰⁰⁸(1 + x + x²)²⁰⁰⁷ = (1 − x)[(1 − x)(1 + x + x²)]²⁰⁰⁷ = (1 − x)(1 − x³)²⁰⁰⁷. The expansion of (1 − x³)²⁰⁰⁷ contains only

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Question ID VK-016649