JEE Main 2024 Physics question
0.08 kg air is heated at constant volume through 5°C. The specific heat of air at constant volume is 0.17 kcal/kg°C and J = 4.18 joule/cal. The change in its internal energy is approximately.
Answer: (A)
Solution
ΔU = ΔT = 0.08 × 0.17 × 4.18 × 10³ × 5 ≈ 284 J.