JEE Main 2024 Physics question
A rectangular loop of length 2.5 m and width 2 m is placed at 60° to a magnetic field of 4T. The loop is removed from the field in 10 s. The average emf induced in the loop during this time is :
Answer: (D)
Solution
= −Δφ/Δt with Δφ = −BA cos60° = −4 × 5 × ½ = −10 Wb. So = +10/10 = +1 V.