JEE Main 2024 Physics question
A train is moving with a speed of 12 m/s on rails which are 1.5 m apart. To negotiate a curve of radius 400 m, the height by which the outer rail should be raised with respect to the inner rail is (Given g = 10 m/s²)
Answer: (D)
Solution
tanθ = v²/(rg) = h/w, so h = v²w/(rg) = (12)² × 1.5/(400 × 10) = 0.054 m = 5.4 cm.