JEE Main 2024 Physics question
Two coils have mutual inductance 0.002 H. The current changes in the first coil according to the relation i = i₀sinωt, where i₀ = 5A and ω = 50π rad/s. The maximum value of emf in the second coil is V. The value of α is .
Answer: 2
Solution
φ₂ = Mi₁, so |E| = M i₀ ω cosωt. = 0.002 × 5 × 50π = 0.5π = π/2 V, so α = 2.