The length of the chord of the ellipse x^2 25 + y^2 16 = 1, whose mid point is (1, 25 ), is equal to :

JEE Main 2024 Mathematics question

The length of the chord of the ellipse , whose mid point is , is equal to :

Answer: (B)

The chord with midpoint (1, 2/5) is T = S₁: x/25 + (2/5)y/16 = 1/25 + (4/25)/16, i.e. 8x + 5y − 10 = 0. Substituting y = (10 − 8x)/5

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Question ID VK-016719