JEE Main 2024 Mathematics question

Mathematics Application of Derivatives JEE Main 2024

If the shortest distance of the parabola y² = 4x from the centre of the circle x² + y² – 4x – 16y + 64 = 0 is d then, d² is

(A)20Correct
(B)16
(C)24
(D)36

Answer: (A)

Solution

The centre of the circle is (2, 8). The shortest distance from a point to the parabola is along a normal: y = mx − 2m − m³ passing

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Question ID VK-016729