JEE Main 2024 Physics question
A particle is moving in a straight line. The variation of position 'x' as a function of time 't' is given as x = (t³ – 6t² + 20t + 15) m. The velocity of the body when its acceleration becomes zero is
Answer: (C)
Solution
v = 3t² − 12t + 20 and a = 6t − 12. a = 0 at t = 2 s, where v = 12 − 24 + 20 = 8 m/s.