JEE Main 2024 Physics question
In an a.c. circuit voltage and current are given by : V = 100 sin (100t) V and I = 100 sin(100t + π/3) mA respectively. The average power dissipated in one cycle is :
Answer: (B)
Solution
P = cosφ = (100/√2)(100 × 10⁻³/√2) cos(π/3) = 5 × 0.5 = 2.5 W.