JEE Main 2024 Physics question
A simple harmonic oscillator has an amplitude A and time period 6π second. Assuming the oscillation starts from its mean position, the time required by it to travel from x = A to x = (√3/2)A will be π/x s, where x = .
Answer: 2
Solution
x = A sin θ: x = A corresponds to θ = 90° and x = (√3/2)A to θ = 60°, so Δθ = 30° = T/12 in time. t = T/12 = 6π/12 = π/2 = π/x, so x = 2.