JEE Main 2024 Physics question
A particle is moving in a circle of radius 50 cm in such a way that at any instant the normal and tangential components of it's acceleration are equal. If its speed at t = 0 is 4 m/s, the time taken to complete the first revolution will be s, where α = .
Answer: 8
Solution
Equal components give v²/r = |dv/dt|. Taking the speed as increasing, v(dv/ds) = v²/r gives v = v₀, and after one revolution (s =
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