JEE Main 2024 Chemistry question
The half-life of radioisotope bromine-82 is 36 hours. The fraction which remains after one day is × 10⁻². (Given antilog 0.2006 = 1.587)
Answer: 63
Solution
λ = 2.303 log 2/36 = (2.303/24) log(N₀/, which gives log(N₀/ =
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