JEE Main 2024 Chemistry question
Molality of 0.8 M H₂SO₄ solution (density 1.06 cm⁻³) is × 10⁻³ m.
Answer: 815
Solution
Molality = (M × 1000)/(1000 d − M × Molar mass) = (0.8 × 1000)/(1000 × 1.06 − 0.8 × 98) = 800/981.6 = 0.815 = 815 × 10⁻³ m.
Molality of 0.8 M H₂SO₄ solution (density 1.06 cm⁻³) is × 10⁻³ m.
Molality = (M × 1000)/(1000 d − M × Molar mass) = (0.8 × 1000)/(1000 × 1.06 − 0.8 × 98) = 800/981.6 = 0.815 = 815 × 10⁻³ m.