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JEE Main 2024 Chemistry question

ChemistrySome Basic Concepts of ChemistryJEE Main 2024

If 50 mL of 0.5 M oxalic acid is required to neutralize 25 mL of NaOH solution, the amount of NaOH in 50 mL of given NaOH solution is g.

Answer: 4

Solution

Equivalents of H₂C₂O₄ = equivalents of NaOH: 0.5 × 50 × 10⁻³ × 2 = M × 25

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Question ID VK-016803