Let y = _e ( 1 - x^2 1 + x^2 ), −1 < x < 1. Then at x = 1/2, the value of 225(y′ – y″) is equal to

JEE Main 2024 Mathematics question

Let , −1 < x < 1. Then at x = 1/2, the value of 225(y′ – y″) is equal to

Answer: (D)

y′ = −2x/(1 − x²) − 2x/(1 + x²) = −4x/(1 − x⁴) and y″ = −4(1 + 3x⁴)/(1 − x⁴)². At x = 1/2: y′ = −2/(15/16) =

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Question ID VK-016821