JEE Main 2024 Physics question
The explosive in a hydrogen bomb is a mixture of ₁H², ₁H³ and ₃Li⁶ in some condensed form. The chain reaction is given by ₃Li⁶ + ₀n¹ → ₂He⁴ + ₁H³ ₁H² + ₁H³ → ₂He⁴ + ₀n¹ During the explosion the energy released is approximately [Given : M(Li) = 6.01690 amu, M(₁H²) = 2.01471 amu, M(₂He⁴) = 4.00388 amu, and 1 amu = 931.5 MeV]
Answer: (A)
Solution
Adding the two reactions, the neutron and ₁H³ cancel: ₃Li⁶ + ₁H² → 2₂He⁴.
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