JEE Main 2024 Physics question
A block of mass 100 kg slides over a distance of 10 m on a horizontal surface. If the co-efficient of friction between the surface is 0.4, then the work done against friction (in J) is :
Answer: (B)
Solution
= μmg x = 0.4 × 100 × 10 × 10 = 4000 J.