JEE Main 2024 Physics question
The electric current through a wire varies with time as I = I₀ + βt, where I₀ = 20 A and β = 3 A/s. The amount of electric charge crossed through a section of the wire in 20 s is:
Answer: (D)
Solution
Δq = ∫₀²⁰(20 + 3t)dt = [20t + 3t²/2]₀²⁰ = 400 + 600 = 1000 C.