JEE Main 2024 Physics question
A cylinder is rolling down on an inclined plane of inclination 60°. It's acceleration during rolling down will be m/s², where x = (use g = 10 m/s²)
Answer: 10
Solution
a = g sinθ/(1 + I/mR²) with I = mR²/2 gives a = (2/3)g sin60° = (2/3)(10)(√3/2) = 10/√3 m/s², so x = 10.