JEE Main 2024 Physics question
When the displacement of a simple harmonic oscillator is one third of its amplitude, the ratio of total energy to the kinetic energy is , where x = .
Answer: 9
Solution
T.E/K.E = (½kA²)/(½k(A² − x²)) = 1/(1 − 1/9) = 9/8, so x = 9.