JEE Main 2024 Chemistry question

ChemistrySolutionsJEE Main 2024

The osmotic pressure of a dilute solution is 7 × 10⁵ Pa at 273 K. Osmotic pressure of the same solution at 283 K is × 10⁴ Nm⁻².

Answer: 73

Solution

For the same solution, P ∝ T: P₂ = 7 × 10⁵ × (283/273) = 7.256 × 10⁵ Pa ≈ 72.56 × 10⁴ ≈ 73 × 10⁴ N m⁻².

Question ID VK-016885