JEE Main 2024 Chemistry question

ChemistryElectrochemistryJEE Main 2024

The mass of zinc produced by the electrolysis of zinc sulphate solution with a steady current of 0.015 A for 15 minutes is × 10⁻⁴ g. (Atomic mass of zinc = 65.4 amu)

Answer: 46

Solution

Q = It = 0.015 × 900 = 13.5 C. Zn²⁺ + 2e⁻ → Zn, so the mass of Zn = (13.5 × 65.4)/(2 × 96500) = 45.75 × 10⁻⁴ g ≈ 46 × 10⁻⁴ g.

Question ID VK-016886