JEE Main 2024 Chemistry question
For the reaction N₂O₄(g) ⇌ 2NO₂(g), = 0.492 atm at 300 K. for the reaction at same temperature is × 10⁻². (Given : R = 0.082 L atm mol⁻¹ K⁻¹)
Answer: 2
Solution
= with Δ = 1: 0.492 = .082 × 300), so = 0.492/24.6 = 2 × 10⁻².