JEE Main 2024 Mathematics question

Mathematics Sequence and Series JEE Main 2024

In an A.P., the sixth term a₆ = 2. If the product a₁a₄a₅ is the greatest, then the common difference of the A.P. is equal to

(A)5/8
(B)2/3
(C)3/2
(D)8/5Correct

Answer: (D)

Solution

Let the first term be a and the common difference d, so a + 5d = 2. Then P = a₁a₄a₅ = (2 − 5d)(2 − 2d)(2 − d). dP/dd = −2[15d² −

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Question ID VK-016904