JEE Main 2024 Mathematics question

Not in JEE Main syllabus

If α, −π/2 < α < π/2 is the solution of 4cosθ + 5sinθ = 1, then the value of tanα is-

Answer: (B)

Solution

Dividing 4cosα + 5sinα = 1 by cosα gives 4 + 5tanα = secα. Squaring, 16 + 25t² + 40t = 1 + t², so 24t² + 40t + 15 = 0

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Question ID VK-016905