JEE Main 2024 Mathematics question
Let and |2A|³ = 2²¹ where α, β ∈ ℤ, then a value of α is-
Answer: (A)
Solution
|2A| = 2(4α² − 4β²) = 8(α² − β²). So |2A|³ = 512(α² − β²)³ = 2²¹ gives (α²
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