If f(x) = cases 2 + 2x, & -1 x < 0 1 - x3, & 0 x 3 cases ; g(x) = cases -x, & -3 x 0 x, & 0 < x 1 cases , then range of (fog)(x) is-

JEE Main 2024 Mathematics question

If ; , then range of (fog)(x) is-

Answer: (A)

g(x) = |x| on [−3, 1], so g(x) ∈ [0, 3]. For g(x) in [0, 3], f(g(x)) = 1 − g(x)/3, and g(x) ≥ 0 means

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Question ID VK-016908