Test SeriesFree PYQsExamsPricing

JEE Main 2024 Mathematics question

MathematicsStraight LinesJEE Main 2024

Let (5, a/4) be the circumcentre of a triangle with vertices A(a, –2), B(a, 6) and C(a/4, –2). Let α denote the circumradius, β denote the area and γ denote the perimeter of the triangle. Then α + β + γ is-

Answer: (D)

Solution

A and B lie on the line x = a, so the circumcentre lies on the perpendicular bisector of AB, y = 2. So a/4 = 2 and a = 8, giving A(8, −2), B(8, 6), C(2,

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-016912