JEE Main 2024 Physics question
Escape velocity of a body from earth is 11.2 km/s. If the radius of a planet be one third the radius of earth and mass be one-sixth that of earth, the escape velocity from the planet is :
Answer: (C)
Solution
= √(2GM/R). For the planet, = M/6 and = R/3, so = √(2G(M/6)/(R/3)) = /√2 = 7.9 km/s.