JEE Main 2024 Physics question
A block of mass m is placed on a surface having vertical cross-section given by y = x²/4. If coefficient of friction is 0.5, the maximum height above the ground at which block can be placed without slipping is:
Answer: (D)
Solution
At the limit of equilibrium tanθ = μ. Here dy/dx = x/2 = 1/2 gives x = 1, so y = x²/4 = 1/4 m.