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JEE Main 2024 Physics question

PhysicsExperimental SkillsJEE Main 2024

Two resistance of 100 Ω and 200 Ω are connected in series with a battery of 4 V and negligible internal resistance. A voltmeter is used to measure voltage across 100 Ω resistance, which gives reading as 1 V. The resistance of voltmeter must be Ω.

Answer: 200

Solution

The voltage across the 200 Ω resistor is 3 V, so the loop current is 3/200 A. The

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Question ID VK-016951