JEE Main 2024 Chemistry question
A and B formed in the following reaction are : CrO₂Cl₂ + 4NaOH → A + 2NaCl + 2H₂O, A + 2HCl + 2H₂O₂ → B + 3H₂O
Answer: (B)
Solution
CrO₂Cl₂ + 4NaOH → Na₂CrO₄ (A) + 2NaCl + 2H₂O. Acidified sodium chromate with H₂O₂ gives the blue peroxide CrO₅ (B).