JEE Main 2024 Chemistry question
NO₂ required for a reaction is produced by decomposition of N₂O₅ in CCl₄ as by equation 2N₂O₅(g) → 4NO₂(g) + O₂(g). The initial concentration of N₂O₅ is 3 mol L⁻¹ and it is 2.75 mol L⁻¹ after 30 minutes. The rate of formation of NO₂ is x × 10⁻³ mol L⁻¹ min⁻¹, value of x is . (nearest integer)
Answer: 17
Solution
−Δ[N₂O₅]/Δt = (3 − 2.75)/30 = 0.25/30 mol L⁻¹ min⁻¹. The rate of
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account