JEE Main 2024 Mathematics question
Let a and b be real constants such that the function f defined by be differentiable on ℝ. Then, the value of equals
Answer: (B)
Solution
Continuity at x = 1: 1 + 3 + a = b + 2. Differentiability: f′(1⁻) = 2 + 3 = 5 = b. So b
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account