JEE Main 2024 Mathematics question
Let , α, β ∈ ℝ. Let a vector b⃗ be such that the angle between a⃗ and b⃗ is π/4 and |b⃗|² = 6. If a⃗·b⃗ = 3√2, then the value of (α² + β²)|a⃗ × b⃗|² is
Answer: (C)
Solution
a⃗·b⃗ = |a||b|cos(π/4) = |a|√6/√2 = 3√2 gives |a| = √6, so 1 + α² + β² = 6 and α² + β² = 5.
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account