JEE Main 2024 Mathematics question
Let f : ℝ → ℝ be defined as f(x) = ae²ˣ + beˣ + cx. If f(0) = −1, f′ 2) = 21 and , then the value of |a + b + c| equals
Answer: (D)
Solution
f(0) = a + b = −1; f′(ln2) = 8a + 2b + c = 21; and ∫₀^{ln4}(ae²ˣ + beˣ)dx = 15a/2 + 3b =
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