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JEE Main 2024 Physics question

PhysicsElectrostatic Potential and CapacitanceJEE Main 2024

A capacitor of capacitance C and potential V has energy E. It is connected to another capacitor of capacitance 2C and potential 2V. Then the loss of energy is E, where x is .

Answer: 2

Solution

The common potential is = (CV + 2C·2V)/(3C) = 5V/3. The initial energy is ½CV² + ½(2C)(4V²) = (9/2)CV², the

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Question ID VK-017037