JEE Main 2024 Physics question
The displacement and the increase in the velocity of a moving particle in the time interval of t to (t + 1) s are 125 m and 50 m/s, respectively. The distance travelled by the particle in (t + 2)ᵗʰ s is m.
Answer: 175
Solution
The increase in velocity in 1 s gives a = 50 m/s². The distance in the nth second is Sₙ = u +
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