Test SeriesFree PYQsExamsPricing

JEE Main 2024 Mathematics question

MathematicsStatisticsJEE Main 2024

Let M denote the median of the following frequency distribution | Class | 0-4 | 4-8 | 8-12 | 12-16 | 16-20 | |---|---|---|---|---|---| | Frequency | 3 | 9 | 10 | 8 | 6 | Then 20M is equal to:

Answer: (C)

Solution

N = 36 and N/2 = 18. The cumulative frequencies are 3, 12, 22, 30, 36, so the median class

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-017079