JEE Main 2024 Mathematics question
The maximum area of a triangle whose one vertex is at (0, 0) and the other two vertices lie on the curve y = –2x² + 54 at points (x, y) and (–x, y) where y > 0, is :
Answer: (D)
Solution
The area is ½|2xy| = |xy| = |x(−2x² + 54)| for x ∈ (−3√3, 3√3). dA/dx = −6x² + 54 = 0
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