JEE Main 2024 Mathematics question
If d₁ is the shortest distance between the lines x + 1 = 2y = –12z, x = y + 2 = 6z – 6 and d₂ is the shortest distance between the lines , , then the value of is :
Answer: 16
Solution
The first pair is (x + 1)/(−12) = y/(−6) = z/1 and x/6 = (y + 2)/6 = (z − 1)/1, giving n⃗₁ × n⃗₂ = 6(−2î + 3ĵ − 6k̂) of magnitude 42 and A₁A₂ = î − 2ĵ + k̂, so d₁ = |6(−2 − 6 −
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