JEE Main 2024 Physics question
The mass number of nucleus having radius equal to half of the radius of nucleus with mass number 192 is
Answer: (D)
Solution
R ∝ , so (r₁/r₂)³ = A₁/A₂: 8 = 192/A₂, giving A₂ = 24.
The mass number of nucleus having radius equal to half of the radius of nucleus with mass number 192 is
R ∝ , so (r₁/r₂)³ = A₁/A₂: 8 = 192/A₂, giving A₂ = 24.