JEE Main 2024 Physics question
The speed of sound in oxygen at S.T.P. will be approximately (given, R = 8.3 JK⁻¹, γ = 1.4)
Answer: (A)
Solution
v = √(γRT/M₀) = √(1.4 × 8.3 × 273.15/(32 × 10⁻³)) ≈ 314 m/s, i.e. about 310 m/s.
The speed of sound in oxygen at S.T.P. will be approximately (given, R = 8.3 JK⁻¹, γ = 1.4)
v = √(γRT/M₀) = √(1.4 × 8.3 × 273.15/(32 × 10⁻³)) ≈ 314 m/s, i.e. about 310 m/s.