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JEE Main 2024 Physics question

PhysicsSystems of Particles and Rotational MotionJEE Main 2024

Two identical spheres each of mass 2 kg and radius 50 cm are fixed at the ends of a light rod so that the separation between the centers is 150 cm. Then, moment of inertia of the system about an axis perpendicular to the rod and passing through its middle point is x/20 kg m², where the value of x is .

Answer: 53

Solution

For each sphere I = (2/5)mr² + m(ℓ/2)² with r = 0.5 m and ℓ/2 = 0.75 m. So for both

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Question ID VK-017218