JEE Main 2024 Chemistry question

Chemistry Some Basic Concepts of Chemistry JEE Main 2024

A sample of CaCO₃ and MgCO₃ weighed 2.21 g is ignited to constant weight of 1.152 g. The composition of mixture is: (Given molar mass in g mol⁻¹ CaCO₃ : 100, MgCO₃ : 84)

(A)1.187 g CaCO₃ + 1.023 g MgCO₃Correct
(B)1.023 g CaCO₃ + 1.187 g MgCO₃
(C)1.023 g CaCO₃ + 1.023 g MgCO₃
(D)1.187 g CaCO₃ + 1.187 g MgCO₃

Answer: (A)

Solution

Let the mass of CaCO₃ be x g; MgCO₃ is (2.21 − x) g. On ignition CaCO₃ → CaO (56 per 100) and MgCO₃ → MgO (40

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Question ID VK-017240