JEE Main 2024 Chemistry question
If 5 moles of an ideal gas expands from 10 L to a volume of 100 L at 300 K under isothermal and reversible condition then work, w, is −x J. The value of x is . (Given R = 8.314 J K⁻¹ mol⁻¹)
Answer: 28721
Solution
w = −2.303 nRT log(V₂/V₁) = −2.303 × 5 × 8.314 × 300 × log 10 = −28720.7 J, so x = 28721 to the nearest integer.