JEE Main 2024 Chemistry question
Number of moles of H⁺ ions required by 1 mole of MnO₄⁻ to oxidise oxalate ion to CO₂ is .
Answer: 8
Solution
16H⁺ + 2MnO₄⁻ + 5C₂O₄²⁻ → 10CO₂ + 2Mn²⁺ + 8H₂O. So 1 mole of MnO₄⁻ requires 8 moles of H⁺.
Number of moles of H⁺ ions required by 1 mole of MnO₄⁻ to oxidise oxalate ion to CO₂ is .
16H⁺ + 2MnO₄⁻ + 5C₂O₄²⁻ → 10CO₂ + 2Mn²⁺ + 8H₂O. So 1 mole of MnO₄⁻ requires 8 moles of H⁺.