The number of solutions, of the equation e^ sin x − 2e^ −sin x = 2, is

JEE Main 2024 Mathematics question

Not in JEE Main syllabus

The number of solutions, of the equation − = 2, is

Answer: (A)

Let y = > 0. Then y − 2/y = 2 gives y² − 2y − 2 = 0, so y = 1 + √3.

Create a free account to read the complete working, and practise questions like this in a timed test.

Question ID VK-017271